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There's also a large object heap for unmanaged code, but it's inside the regular heap

| Monday, October 3, 2011
Occasionally, a customer will ask for assistance explaining some strange heap behavior, or at least heap behavior that appears to be strange if you assume that the heap behaves purely classically.

    I need to understand the heap behavior we're seeing. I have a sample program which allocates five blocks of memory from the process heap, each of size 100 bytes. When we dump the heap blocks with the !heap -x command, we find that all of them belong to the same heap segment, and when we do a !vadump -v, we find that they all live on the same page. On the other hand, if we allocate five blocks of size 512KB, then we find that each one gets placed in its own virtually-allocated range, and the range is not size 512KB but rather 516KB.

    Questions:

        Why does the system combine the 100-byte allocations? Why is there no extra overhead for the small allocations, but the large allocations have a 4KB overhead?
        Why does the system allocate a separate virtual address range for the 512KB block? Which component makes this decision and what are the factors involved?
        Why does allocating a 512KB block require 4KB of overhead?
        Is there any documentation for this behavior?

Let's look at the last question first. There is no documentation for this behavior because it is all implementation detail. All the heap is required to do is return you a block of memory of the size you requested. How it goes about getting this memory block is at the discretion of the heap manager, and as we've seen in the past, the precise algorithm has varied over time.

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